Find the value of k, if x – 1 is a factor of p(x) in p(x) = kx^2-√

1.	Find the value of k, if x – 1 is a factor of p(x) in p(x) = kx^2-√2x+1
Answer» ONG>ANSWER: $\boxed{k=\sqrt{2}-1}$ Step-by-step EXPLANATION: $p(x)=kx^2-\sqrt{2}x+1 \\\\ x-1 \ is \ a \ factor \\ =>x-1=0\\=>x=+1 \\\\ Put \ x=1,\\ kx^2-\sqrt{2}x+1=0 \\ k(1)^2-\sqrt{2}(1)+1=0 \\ k-\sqrt{2}+1=0 \\ k=\sqrt{2}-1$

Find the value of k, if x – 1 is a factor of p(x) in p(x) = kx^2-√2x+1

Answer» ONG>ANSWER:

$\boxed{k=\sqrt{2}-1}$

Step-by-step EXPLANATION:

$p(x)=kx^2-\sqrt{2}x+1 \\\\ x-1 \ is \ a \ factor \\ =>x-1=0\\=>x=+1 \\\\ Put \ x=1,\\ kx^2-\sqrt{2}x+1=0 \\ k(1)^2-\sqrt{2}(1)+1=0 \\ k-\sqrt{2}+1=0 \\ k=\sqrt{2}-1$

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Find the value of k, if x – 1 is a factor of p(x) in p(x) = kx^2-√2x+1

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