Find the value of K, if the roots of the equation (3K + 1)x2 + (11 + K

1.	Find the value of K, if the roots of the equation (3K + 1)x2 + (11 + K)x + 9 = 0 are equal
Answer» $\text{since, \:roots\: are \:equal.}$ $hence, D = 0$ $so,$ $here a = (3k+1), b = (11+k), c = 9$ $then,$ $D = 0$ ${b}^{2}-4ac = 0$ ${(11+k)}^{2}-4×(3k+1)×9 = 0$ ${(11)}^{2}+{k}^{2}+2×11×k-4×9(3k+1) = 0$ $1331 + {k}^{2}+ 22k -36(3k+1) = 0$ $1331 + {k}^{2}+ 22k -108k -36 = 0$ ${k}^{2} +22k-108k+1331-36 = 0$ ${k}^{2} -86k + 1295 = 0$ $\text{Now, \:mid \:term \:split}$ $\text{we \:get,}$ Your QUESTION is LITTLE BIT WRONG I THINK so.