Find the value of k if kx(x+2)+4=0 has distinct real roots

1.	Find the value of k if kx(x+2)+4=0 has distinct real roots
Answer» ANSWER: KX(x+2)+4=0 Step 1: Add -4 to both SIDES. kx2+2kx+4+−4=0+−4 kx2+2kx=−4 Step 2: Factor out variable k. k(x2+2x)=−4 Step 3: Divide both sides by x^2+2x. k(x2+2x) x2+2x = −4 x2+2x k= −4 x2+2x Answer: k= −4 x2+2x Step-by-step EXPLANATION:

Answer»

ANSWER:

KX(x+2)+4=0

Step 1: Add -4 to both SIDES.

kx2+2kx+4+−4=0+−4

kx2+2kx=−4

Step 2: Factor out variable k.

k(x2+2x)=−4

Step 3: Divide both sides by x^2+2x.

k(x2+2x)

x2+2x

−4

x2+2x

−4

x2+2x

Answer:

−4

x2+2x

Step-by-step EXPLANATION:

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Find the value of k if kx(x+2)+4=0 has distinct real roots​

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Find the value of k if kx(x+2)+4=0 has distinct real roots