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Find the value of k for which the roots of 9x2 + 8kx + 16 = 0 are real and equal |
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Answer» Given: 9x2 + 8kx + 16 = 0 Here a = 9,b = 8k and c = 16 It is given that the roots of the equation are real and equal; therefore, we have: D = 0 ⇒ (b2 - 4ac) = 0 ⇒ (8k)2 - 4 x 9 x 16 = 0 ⇒ 64k2 - 576 = 0 ⇒ 64k2 = 576 ⇒ k2 = 9 ⇒ k = ≠3 ∴ k = 3 or k = -3 |
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