1.

Find the value of k for which the roots of 9x2 + 8kx + 16 = 0 are real and equal

Answer»

Given:

9x2 + 8kx + 16 = 0

Here

a = 9,b = 8k and c = 16

It is given that the roots of the equation are real and equal; therefore, we have:

D = 0

⇒ (b2 - 4ac) = 0

⇒ (8k)2 - 4 x 9 x 16 = 0

⇒ 64k2 - 576 = 0

⇒ 64k2 = 576

⇒ k2 = 9

⇒ k = ≠3

∴ k = 3 or k = -3



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