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find the value of k for which the roots are real and real and equal the following equation K - X the whole square + 2 into K - 6 X + 6 is equal to zero |
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Answer» Answer: (K-X)^2+2(K-6X)+6=0 K^2+X^2-2KX+2K-12X+6=0 roots are REAL,REALAND EQUAL is b^2-4ac is >equalto0. X^2-X(2K+6)+(K^2+2K+6)=0. (2K+6)^2-4(1)(K^2+2K+6)>=0. 4(K^2+9+6K)-4K^2-8K-24>=0. 4K^2+36+24K-4K^2-8K-24>=0 16K+12>=0. K=-3/4. |
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