1.

Find the value of k for which the point (1,-2) lies on the graph of the linear equation x - 2y + k = 0.

Answer»

Given, 

(1,-2) lies on the graph of the linear equation x - 2y + k = 0 

Thus, 

(1, -2) satisfies the equation 

⇒ 1 + 4 + k = 0 

⇒ k = - 5



Discussion

No Comment Found