Saved Bookmarks
| 1. |
Find the value of k for which the point (1,-2) lies on the graph of the linear equation x - 2y + k = 0. |
|
Answer» Given, (1,-2) lies on the graph of the linear equation x - 2y + k = 0 Thus, (1, -2) satisfies the equation ⇒ 1 + 4 + k = 0 ⇒ k = - 5 |
|