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find the value of k for which the following system of equations has a unique solutions 1 . kx +2y= 5 , 3x+y=1

Answer»

Answer:

The value of k is all number EXCEPT k=6

Step-by-step explanation:

Given : Equations kx+2y=5,3x+y=1

To find : The value of k for which the FOLLOWING system of equation has a unique solution.

Solution :  

When the system of equation is in FORM ax+by+c=0, dx+ey+f=0 then the CONDITION for a unique solutions is  

\frac{a}{d}\neq\frac{b}{e}

Comparing, a=k , b=2 , c=-5, d=3, e=1, f=-1

Substituting the values,

\frac{k}{3}\neq\frac{2}{1}

Cross multiply,

k\times 1\neq 2\times 3

k\neq 6

Therefore, The value of k is all number except k=6



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