Saved Bookmarks
| 1. |
Find the value of k for which the following systemsof linear equations has an infinite number of solutions2x+3y = 7,(k-1)x + (K+2)y=3K. |
|
Answer» Answer: Step-by-step explanation: If 2x + 3y =7 then , X = 2 y = 1 so , by this :- (k-1)2+(k+2)1=3k 2k-2+k+2=3k 3k=3k 3k-3k=0 0=0 and then if we CHECK it (0-1)2+(0+2)1=3(0) (-1)2+(2)1=0 -2+2=0 0=0 |
|