1.

Find the value of k 3k²=4(kx-1) ,if the root is equal​

Answer»

Solution :

3k² = 4(KX - 1)

for quadratic EQUATION are

b² + 4AC = 0

so, now

3kx² - 4 kx + 4 = 0

b² + 4ac = (-4k)² + 4 × 3k × 4 = 0

16k² + 12k × 4 = 0

16k² - 48k = 0

16k (k - 3) = 0

16k = 0 or k - 3 = 0

k = 0 or k = 3

∴ value of k is (0 , 3)



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