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Find the value of k 3k²=4(kx-1) ,if the root is equal |
Answer» Solution :3k² = 4(KX - 1) for quadratic EQUATION are b² + 4AC = 0 so, now 3kx² - 4 kx + 4 = 0 b² + 4ac = (-4k)² + 4 × 3k × 4 = 0 16k² + 12k × 4 = 0 16k² - 48k = 0 16k (k - 3) = 0 16k = 0 or k - 3 = 0 k = 0 or k = 3 ∴ value of k is (0 , 3) |
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