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Find the value of : (i) `sin 30^(@)+cos 60^(@)` (ii) `sin 0^(@)-cos 0^(@)` (iii) `tan 45^(@)- tan 37^(@)` (iv) `sin 390^(@)` (v) `cos 405^(@)` (vi) `tan 420^(@)` (vii) `sin 150^(@)` (viii) `cos 120^(@)` (ix) `tan 135^(@)` (x) `sin (330^(@))` (xi) `cos 300^(@)` (xii) `sin (-30^(@))` (xiii) `cos (-60^(@))` (xiv) `tan (-45^(@))` (xv) `sin (-150^(@))` |
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Answer» (i) `sin 30^(@)+cos 60^(@)=1/2+1/2=1" "` (ii) `sin 0^(@)-cos 0^(@)=0-1=-1` (iii) `tan 45^(@)-tan 37^(@)=1-3/4=1/4" "` (iv) `sin 390^(@)=sin (360^(@)+30^(@))=sin 30^(@)=1/2` (v) `sin 150^(@)= sin (90^(@)+60^(@))=cos 45^(@)=1/sqrt(2)" "` (vi) `tan 420^(@)=tan (360^(@)+60^(@))= tan 60^(@)=sqrt(3)` (vii) `sin 150^(@)= sin (90^(@)+60^(@))=cos 60^(@)=1/2` or `sin 150^(@)= sin (180^(@)-30^(@))= sin 30^(@)=1/2` (viii) `cos 120^(@)= cos (180^(@)-60^(@))=- cos 60^(@)=-1/2" "` (ix) `tan 135^(@)=tan (180^(@)-45^(@))=-tan 45^(@)=-1` (x) `sin 330^(@)= sin (360^(@)-30^(@))=- sin 30^(@)=-1/2" "` (xi) `cos 300^(@)=cos (360^(@)-60^(@))= cos 60^(@)=1/2` (xii) `sin (-30^(@))=-sin 30^(@)-=1/2 " "` (xiii) `cos (-60^(@))=+ cos 60^(@)=1/2` (xiv) `tan (-45^(@))=-tan 45^(@)=-1` (xv) `sin (-150^(@))=-sin (150^(@))=- sin (180^(@)-30^(@))=- sin 30^(@)=-1/2` |
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