Find the value of Cv and Cp for nitrogen. (Given R = 8.3 J mol-1 K-1

1.	Find the value of Cv and Cp for nitrogen. (Given R = 8.3 J mol-1 K-1 ; also, for a diatomic gas, Cv = \(\frac{5}{2}\) R.
Answer» Nitrogen is known to exist as a diatomic molecule. Hence C_v(for nitrogen) = \(\frac{5R}{2}\) = \(\frac{5}{2}\) × 8.3 J mol^-1K^-1 = 20.75 J mol^-1 K^-1 From Mayer’s relation, C_p = C_v + R C_p(for nitrogen) = (20.75 + 8.3) J mol^-1 K^-1 = 29.05 K mol^-1 K ^-1

Find the value of Cv and Cp for nitrogen. (Given R = 8.3 J mol-1 K-1 ; also, for a diatomic gas, Cv = \(\frac{5}{2}\) R.

Answer»

Nitrogen is known to exist as a diatomic molecule. Hence

C_v(for nitrogen) = \(\frac{5R}{2}\)

= \(\frac{5}{2}\) × 8.3 J mol^-1K^-1

= 20.75 J mol^-1 K^-1

From Mayer’s relation, C_p = C_v + R

C_p(for nitrogen) = (20.75 + 8.3) J mol^-1 K^-1

= 29.05 K mol^-1 K ^-1