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Find the value of cos(3π2+x)cos(2π+x)[cot(3π2−x)+cot(2π+x)]. Given, sin2x+cos2x=1

Answer»

Find the value of cos(3π2+x)cos(2π+x)[cot(3π2x)+cot(2π+x)].
Given, sin2x+cos2x=1



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