1.

Find the value of a and b in 3/√3-√2 = a√3-b√2​

Answer»

Answer:

3/sqrt3-sqrt2 ×sqrt3+sqrt2/sqrt3+sqrt2=asqrt3-bsqrt2

since by RATIONALIZING the denominator

3(sqrt3+sqrt2)=asqrt3-bsqrt2

3sqrt3-(-3)sqrt2=asqrt3-bsqrt2

on COMPARING both SIDES we GET a=3 and b=-3



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