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Find the value of a and b if √11-√7\√11+√7=a√77b |
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Answer» √11-√7÷ √11+√7 = √11-√7÷√11+√7× √11-√7÷√11-√7 =( √11-√7 )°2 ÷√11°2 -√7°2 =√11°2 +√7°2 -2×√11×√7÷ 11-7 = 11+7-2√77÷ 4 = 18 -2√77÷4 = 9-√77÷ 2 = a-B√77 = a= 9/2 And b = 1/2
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