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find the value of a and b for which the following system of linear equation has infinite number of solution 2x-3y=0 ; (a+b)x-(a+b-3)y=4a+b |
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Answer» Answer: a1/a2=b1/b2=c1/c2 2/(a+B)=-3/(-a-b+3)=7/4a+b 2/a+b=7/4a+b 8a+2b=7a+7b 1a-5b=0.....1 -3/-a-b+3=7/4a+b -12a-3b=-7a-7b+21 -5a+4b=21....2 1*-5 -5a+25b=0 1-2 -5a+25b=0 -5a+4b=21 21b=-21 b=-1 substituting the VALUE of b in 2 therefore a=5 therefore a and b satisfies EQUATION a+5b=0 5-5=0
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