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Find the value of 3sin^20- 2tan^45+ 2sin^70 |
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Answer» 3sin²20°-2tan²45°+3sin²70°=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²=3sin²20°-2×(1)²+3cos²20°=3(sin²20°+cos²20°)-2=3-2 [∵, sin²20°+cos²20°=1]=1 Ans. This question is wrongRight question is 3sin^2 20° - 2tan^2 45° + 3sin^2 70° |
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