Find the value of 25x^2 + 16y^2 + 40 xy at x=1 and y=-1.

1.	Find the value of 25x^2 + 16y^2 + 40 xy at x=1 and y=-1.
Answer» ong>Answer: GIVEN:- x = 1 & y = -1 Putting the value given in the equation, 25x² + 16y² + 40xy , we get: => 25x² + 16y² + 40XY => 25(1)² + 16(-1)² + 40(1)(-1) => 25 + 16 -40 => 41 - 40 => 1 Hence, 25x² + 16y² + 40xy = 1 I hope it helps U

Answer»

ong>Answer: GIVEN:- x = 1 & y = -1

Putting the value given in the equation, 25x² + 16y² + 40xy , we get:

=> 25x² + 16y² + 40XY

=> 25(1)² + 16(-1)² + 40(1)(-1)

=> 25 + 16 -40

=> 41 - 40

=> 1

Hence, 25x² + 16y² + 40xy = 1

I hope it helps U

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