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Find the value of:(1+cot^2) (1+cos) (1-cos) |
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Answer» Answer:(1 + cot2∅)(1 - cos∅)(1 + cos∅) = 1 {USE , (a + B)(a - b) = a² - b² } (1 + cot2∅)( 1 - cos²∅) = 1 [ use, 1 - cos²x = sin²x] (1 + cot2∅)(sin²∅) = 1 ( 1 + tan2∅)(sin²∅) = tan2∅ use, FORMULA, tan2∅ = 2tan∅/(1 - tan²∅) ( 1 - tan²∅ +2tan∅)sin²∅/(1 - tan²∅) = 2tan∅/( 1 - tan²∅) (1 -tan²∅+ 2tan∅)sin²∅ = 2tan∅ ( 1 - tan²∅+2tan∅)/cosec²∅ = 2tan∅ ( 1 - tan²∅ + 2tan∅)/(1 + cot²∅) = 2tan∅ ( 1 - tan²∅ + 2tan∅)tan∅/(1 +tan²∅) = 2 tan∅ - tan³∅ +2tan²∅ = 2 + 2 tan²∅ tan³∅ - tan∅ +2 = 0 Read more on Brainly.in - brainly.in/question/1270767#readmore Step-by-step explanation: |
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