Saved Bookmarks
| 1. |
Find the value of `0.3258.` |
|
Answer» Let `R=0.3258` `implies R= 0.32585858585"....." " " "......(i)"` Here, number of figures which are not recurring is 2 and number of figures which are recurring is also 2. Then, `100R= 32.585858585"....." " " "......(ii)"` and `10000R= 3258.585858585"....." " " "......(iii)"` On subtracting Eq.(ii) from Eq.(iii), we get `9900R= 3226` `therefore " " R= (3226)/(9900)` Hence, `" " R= (1613)/(4950)` |
|