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Find the vale2 the value of k for which x = 1 is a root of the equation+3 = 0. Also, find the other root. |
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Answer» x=1 is the rootso put value of x in the equatiin we getx²+kx+3=01²+k(1)+3=01+k+3=04+k=0k=-4put the value of k in the equationnow the equation becomesx²-4x+3=0x²-3x-1x+3=0x(x-3)-1(x-3)=0(x-3)(x-1)=0x-3=0 or x-1=0x=3 or x=1therefore the other root is x=3 X = 1 P(X) = X²+KX-3 Putting X = 1 P(1) = (1)² + K × 1 +3 => 1 + K + 3 = 0 => K = -4 P(X) = X²-4X+3 => X²-3X-X+3 => X(X-3) -1(X-3) => (X-3) (X-1) => X-3 = 0. OR X-1 = 0 => X = 3. OR X = 1 Hence, the Value of K is -4 and 3 , 1 are the two zeros of the polynomial X²-4X+3 if x = 1 is a root then ,(1)^2+k(1)+3=0or , 1+k+3=0or , k=-4 |
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