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Find the unit vector perpendicular to the plane containing the vectors ] = (41+ 21 - k) and Q = (3î – ĵ + k). Also find the area of the parallelogram formed by the two vectors. |
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Answer» We know that a×B is VECTOR perpendicular to the plane of a and bTherefore unit vector perpendicular to the plane of a and b = ∣a×b∣a×b Now a×b=(2i−j+K)×(3i+4j−k)= ∣∣∣∣∣∣∣∣ i23 j−14 k1−1 ∣∣∣∣∣∣∣∣ =i(1−4)+j(3+2)+k(8+3)=−3i+5j+11k⇒ unit vector PARALLEL to a×b= ∣a×b∣a×b = (3 2 +5 2 +11 2 ) −3i+5j+11k = 155 −3i+5j+11k |
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