Saved Bookmarks
| 1. |
Find the unit vector perpendicular to plane ABC where the position vector of A,B and C are `2 hat i-hat j+hat k, hat i+hat j+2 hat k` and `2 hat i+3 hat k` respectively. |
|
Answer» `vec(AB)=vecB-vecA=hati+haty+2hatk` `=-(2hati-hatj+hatk)=-hati+2hatj+hatk` `vec(BC)=vecC-vecB=2hati+3hatk-hati-hatj-2hatk` `=hati-hatj+hatk` Perpendicular vector=`3hati+2hatj-1hatk` Unit vector=`(vec(AB)*vec(BC))/(|vec(AB)*vec(BC)|)` `=(3hati+2hatj-hatk)/sqrt(3^2+2^2+1^2` `=(3hati+2hatj-hatk)/sqrt15` |
|