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Find the two parallel sides of a trapezium whose area is 1.6 m2, altitude is 10 dmand one of the parallel sides is longer than the other by 8 dm. |
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Answer» area = 1.6m²= 160dm² now area = (1/2)*(sum of sides)*(h)=> 1/2*(8+x)*(10) = 160 => x+8 = 16*2=32 =>x=32-8=24 the other side is 24dm. thanks |
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