Find the total surface area of a cuboid with dimensions 10cm,6cm and 4

1.	Find the total surface area of a cuboid with dimensions 10cm,6cm and 4cm
Answer» $\bf \: \underline{ Given} :$ ↴ $\sf \implies Length = 10 \: cm$ $\sf \implies Breadth = 6 \: cm$ $\sf \implies Height = 8 \: cm$ $\bf \: \underline{To \: find} :$ ↴ $\sf \implies Total \: surface \: area \: of \: cuboid.$ $\bf \: \underline{Formula \: to \: be \: used},$ $\boxed{ \sf \: Total \: surface \: area \: of \: cuboid = \red{2(LB +BH + HL)}\: Sq.unit}$ $\sf \: Where,$ $\sf \bull \: \implies \:L = Length$ $\sf \bull \: \implies \:B = Breadth$ $\sf \bull \: \implies \:H = Height$ $\sf \: Therefore,$ $\sf \: \underline{Putting \: the \: values} \: :$ ↴ $\sf \implies \sf \: {2 \: (10 \times 6 +6 \times 8+ 8 \times 10)}$ $\sf \implies \sf \: {2 \: (60+48+ 80)}$ $\sf \implies \sf \: {2 \: (108+ 80 )}$ $\sf \implies \sf \: {2 \: (188)}$ $\sf \implies\sf { \: 2 \: \times 188}$ $\sf \implies \sf \: 376$ $\underline{ \boxed{\pink{ \sf \: Hence \: total \: surface \: area \: of \: cuboid = 376\: cm^{2}}}}$ $\underline{\sf Some \: more \: information \: about \: Cuboid} :$ ↴ $\sf \: 1. \: Volume \: of \: cuboid : (Length \times Breadth \times Height) \: \underline{ Cubic \: units}$ $\sf \: 2. \: Diagonal \: of \: Cuboid : \sqrt{(L^{2} + B^{2} + H^{2}) }\: units$ $\sf\:3. \: Perimeter \: of \: cuboid : 4 \: (length + breadth + height)\:Sq.units$ $\sf \: 4. \: Total \: surface \: area : 2(LB +BH + HL)\: Sq.units$ $\sf \: 5. \: Lateral \: Surface \: area : 2 \: height \: (length + breadth) \: Sq.units$