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Find the total number of electrons in a molecule of phosphoric acid `(H_(3)PO_(4))`. |
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Answer» Atomic No. of P=15 , O=8 and H=1 A molecule of `H_(3)PO_(4)=3 H`atoms + 1 P atom + 4 O atoms `:.` Total no of electrons present `=3xx1+1xx15+4xx8=50`. |
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