Find the three consecutive numbers where the sum of twice of first num

1.	Find the three consecutive numbers where the sum of twice of first number, thrice of second number and four times of third number is 182.
Answer» Let three consecutive numbers be x, x + 1 and x + 2. Then according to question 2x + 3(x + 1) + 4 (x + 2) = 182 ⇒ 2x + 3x + 3 + 4x + 8 – 182 ⇒ 9x + 11 = 182 ⇒ 9x = 182 – 11 ⇒ 9x = 171 ⇒ x = 171/9 = 19 Hence, the first number = 19 second number = 19 + 1 = 20 and third number = 19 + 2 = 21

Find the three consecutive numbers where the sum of twice of first number, thrice of second number and four times of third number is 182.

Answer»

Let three consecutive numbers be x, x + 1 and x + 2.

Then according to question 2x + 3(x + 1) + 4 (x + 2) = 182

⇒ 2x + 3x + 3 + 4x + 8 – 182

⇒ 9x + 11 = 182

⇒ 9x = 182 – 11

⇒ 9x = 171

⇒ x = 171/9 = 19

Hence, the first number = 19

second number = 19 + 1 = 20

and third number = 19 + 2 = 21