1.

Find the the first term of the given sequence 14th term is 68 common difference 3​

Answer»

ANSWER:

X1=?

X14=68

d=3

X1+13d=X14

X1+13×3=64

X1+39=68

X1=68-39=29

X1 FIRST TERM =29

Hope it HELPS you.....



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