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Find the sum to n terms of the sequence,8,88,888,8888.....

Answer» 8(1,11,111,1111.......)Divide and multiply by 98/9(9,99,999....)8/9(10-1,100-1,1000-1.....)8/9((10,100,1000.....)-n)After that sum of 10 100 1000.... so on and it will be your answer


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