1.

Find the sum of zeroes of the polynomial p(x) =-18x²+7k

Answer»

P(x) = - 18x^2 + 0x + 7k

On COMPARING given polynomial with general quadratic polynomial, we get

a = - 18

b = 0

c = 7k

Sum of ZEROES = - b/ a

= - 0 / - 18

= 0



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