1.

Find the sum of the first 15 multiples of 8

Answer»

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First Term (a) = 8
Common Difference (d) = 8
Number of TERMS (n) = 15

So, Sn = n/2 [2A + (n-1)d ]
Sn = 15/2 [2(8) + 14(8)]
Sn = 15/2 [16 + 112]
Sn = 15/2 [128].
Sn = 15 [64]
Sn = 960.....
So,Sum of first 15 multiples of 8 is 960✔✔
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