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Find the sum of n terms of the series 4-+44 |
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Answer» we have to find:-the sum of4-1/n, 4-2/n, 4-3/n = ? solution:-we know that :1 + 2 +3 + 4 +5 +6 + ...........+ n = n(n +1) / 2and1 + 1+ 1 + 1 + 1 + .............+ n = n Here, sum of 4-1/n, 4-2/n, 4-3/n up to the nth term = (4 + 4 + 4 + 4 + 4 + ......... upto n terms) + (-1/n - 2/n - 3/n - ..........upto n terms) = 4 ( 1+1+1+1.......... upto n terms) - 1/n (1 + 2 + 3 +4 .........upto n terms) = 4 n - 1/n× n(n +1)/2 = 4n - (n+1)/2 = [ 8n - (n+1) ] / 2 .......taking L.C.M =( 7n - 1) / 2 Answer |
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