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Find the sum of first 24 terms of the list of numbers whose nth term is given by an = 3 + 2n. |
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Answer» xn = 3 + 2n Now, put n = 1,2,3,.... x1 = 3 + 2 x 1 = 5 x2 = 3 + 2 x 2 = 7 x3 = 3 + 2 x 3 = 9 Thus, the terms of the AP are 5, 7, 9 Here, f = 5 and d = 2 \(S_{24}=\frac{24}{2}[2\times5+(24-1)\times2]\) = 12/10 + 46l = 672 |
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