1.

Find the sum of all three digits number which are divisible by 7 by Arithmetic Progression class 10​

Answer»

105,112,119,......994

last term = 994

=> a + (N-1)d = 994

=> 105 + (n-1)7 = 994

=> (n-1)7 = 889

=> n - 1 = 127

=> n = 128

Sn =  \frac{128}{2} (105 + 994) \\  \\  = 64 \times 1099 \\  \\  = 70336



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