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Find the sum of all three diGit number which are divisible by 7 |
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Answer» 3-digit numbers divisible by 7: First = 105 LAST = 994 Number of TERMS: N = (Last - First)/(7) + 1 = 128 Sum of the terms: S = (128/2)×(First + Last) = 64×(105 + 994) S = 70336 ANSWER: sum = 70336 |
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