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Find the sum of all natural number between 200 and 400 which are divisible by 7​

Answer»

The numbers lying between 200 and 400, which are divisible by 7, are 203, 210, 217, ­­­­­­­­… 399 ∴First term, a = 203 Last term, l = 399 Common difference, d = 7 Let the number of terms of the A.P. be n. ∴ an = 399 = a + (n –1) d ⇒ 399 = 203 + (n –1) 7 ⇒ 7 (n –1) = 196 ⇒ n –1 = 28 ⇒ n = 29 s29=29/2 (203+399)       = 29/2(602)       = (29)(301)       =8729       Thus, the REQUIRED sum is 8729. Explanation:



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