1.

Find the sum of all 2 digits natural numbers which are divisible by 4?

Answer»

The TWO DIGITS numbers which are divisible by 4 are
12,16,20,......96  in AP.

Sn = n/2(2a+(n -1)d)

Here a = 12 , d = 4.

tn = a + (n - 1) d

96 = 12 + ( n - 1) 4

84 = ( n - 1) 4

n - 1 = 21

∴n = 22

S22 = (22/2) (2×12 + (22 -1)4)

S22 = 11×[ 24 + 84]

S22 = 11×[ 24 + 84]

∴S22 = 1188.


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