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Find the sum of A.P 2, 7, 12to 10 term. |
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Answer» Solution of this sum is twenty one ( 21 ) a = 2, d= 5; S10= n/2(2a + ( n-1)d) S10= 10/2(2(2)+(10-1)5); = 5 (4+9(5)); = 5 (4 + 45)=5(49)=20+45 = = 245 a=2d=7-2=5s10=n/2{2a+(n-1)d} =10/2(2*2+9*5) =5(4+45) =5*49 =245 245 is the correct answer of the given question a=2, d=5s10=n/2(2a+(n-1)d)s10=10/2(4+45)5=49=245 |
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