Find the sum:(i) (5/8) + (3/10)(ii) 4 (3/4) + 9 (2/5)

1.	Find the sum:(i) (5/8) + (3/10)(ii) 4 (3/4) + 9 (2/5)
Answer» (i) Given (5/8) + (3/10) Taking LCM for 8 and 10 we get 40 Now we have to convert the given fractions into equivalent fractions with denominator 40 (5/8) + (3/10) = (5 × 5)/ (8 × 5) + (3 × 4)/ (10 × 4) = (25/40) + (12/40) = (37/40) (ii) Given 4 (3/4) + 9 (2/5) First convert given mixed fractions into improper fractions. 4 (3/4) + 9 (2/5) = (19/4) + (47/5) Taking LCM for 4 and 5 we get 20 Now we have to convert the given fractions into equivalent fractions with denominator 20 4 (3/4) + 9 (2/5) = (19/4) + (47/5) = (19 × 5)/ (4 × 5) + (47 × 4)/ (5 × 4) = (95/20) + (188/20) = (283/20)

Answer»

(i) Given (5/8) + (3/10)

Taking LCM for 8 and 10 we get 40

Now we have to convert the given fractions into equivalent fractions with denominator 40

(5/8) + (3/10) = (5 × 5)/ (8 × 5) + (3 × 4)/ (10 × 4)

= (25/40) + (12/40)

= (37/40)

(ii) Given 4 (3/4) + 9 (2/5)

First convert given mixed fractions into improper fractions.

4 (3/4) + 9 (2/5) = (19/4) + (47/5)

Taking LCM for 4 and 5 we get 20

Now we have to convert the given fractions into equivalent fractions with denominator 20

4 (3/4) + 9 (2/5) = (19/4) + (47/5) = (19 × 5)/ (4 × 5) + (47 × 4)/ (5 × 4)

= (95/20) + (188/20)

= (283/20)

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