1.

Find the sum and product of zeros of polynomial 2x^3-4x^2+3x-8

Answer»

Hey!!!!

=> 2x³ - 4x² + 3x - 8

So

= > \alpha + \beta + \gamma = \frac{ - b}{a}

= > \alpha + \alpha + \gamma = \frac{4}{2}

= > \alpha + \beta + \gamma = 2

So,

= > \alpha \beta \gamma = \frac{ - d}{a}

= > \alpha \beta \gamma = \frac{8}{2}

= > \alpha \beta \gamma = 4


Hope this helps ✌️


Discussion

No Comment Found

Related InterviewSolutions