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Find the standard equation of hyperbola with vertices (0,±5). and horizontal conjugate axis of length 6units |
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Answer» ONG>Step-by-step EXPLANATION: vertices are GIVEN. i. e, a=5 is given length of conjugate axis = 2B =6 b=3 equation of hyperbola is, y²/a² - x²/b²= 1 y²/25 - x²/9 = 1 Or, 9y² - 25x² =225 |
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