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Find the specific volume, enthalpy and internal energy of wet steam at 18 bar, dryness fraction 0.85. |
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Answer» Pressure of steam, p = 18 bar Dryness fraction, x = 0.85 From steam tables corresponding to 18 bar pressure : hf = 884.6 kJ/kg, hfg = 1910.3 kJ/kg, vg = 0.110 m3/kg, uf = 883 kJ/kg, ug = 2598 kJ/kg. (i) Specific volume of wet steam, v = xvg = 0.85 × 0.110 = 0.0935 m3/kg. (ii) Specific enthalpy of wet steam, h = hf + xhfg = 884.6 + 0.85 × 1910.3 = 2508.35 kJ/kg. (iii) Specific internal energy of wet steam, u = (1 – x)uf + xug = (1 – 0.85) × 883 + 0.85 × 2598 = 2340.75 kJ/kg. |
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