1.

Find the solution ? this question is from progressions. ​

Answer»

Step-by-step explanation:

15th term=a+14d

a=2 , d=3

So 2+14×3

2+42=44

15th term=44

Sum of FIRST 10 terms=n/2[2A+(n-1)d]

=10/2[4+(9)3]

=5×31

= 155

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