1.

Find the solution of the differential eqation p2 +y2 =1

Answer»

Step-by-step explanation:

Given, p2 + y2 = 1 ,let this be equation 1

p2 = 1 _ y2 ,let this be equation 2

SUBSTITUTE equation 2 in 1

p2+y2=1 : 1 _ y2 + y2 = 1

1 _ 0 = 1

= 1 _ 1

= 0



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