Find the smallest square number that is divisible by each of the numbe

1.	Find the smallest square number that is divisible by each of the numbers 14, 28 and 32. guys plz help with steps
Answer» ANSWER: 3136 Step-by-step explanation: First Calculate the LCM of 14, 28 and 32. factors of 14= 2x7 Factors of 28 = 2x2x7 factors of 32 = 2x2x2x2x2 So, LCM = 2x7x2x2x2x2 But, since we want it to be a perfect square so, we multiply it by 2 and 7 as it will lead us to perfect square. So, the number is 2x2x2x2x2x2x7x7 49x64 3136 So, the required no. is 3,136. Please! Mark this answer as BRANLIEST.

Find the smallest square number that is divisible by each of the numbers 14, 28 and 32. guys plz help with steps

Answer»

3136

Step-by-step explanation:

First Calculate the LCM of 14, 28 and 32.

factors of 14= 2x7

Factors of 28 = 2x2x7

factors of 32 = 2x2x2x2x2

So, LCM = 2x7x2x2x2x2

But, since we want it to be a perfect square

so, we multiply it by 2 and 7 as it will lead us to perfect square.

So, the number is 2x2x2x2x2x2x7x7

49x64

3136

So, the required no. is 3,136.

Please! Mark this answer as BRANLIEST.