Find the smallest number which leaves remainders 2, 6 and 12 when divi

1.	Find the smallest number which leaves remainders 2, 6 and 12 when divided by 22, 26 and 32 respectively please send me important
Answer» Here (22-2)=20, (26-6)=20, (32-12) = 20. .°. REQUIRED no. = (LCM 22,26,32)-20 22 = 2×11 26 = 2×13 32 = 2×2×2×2×2 = 2^5 LCM = highest power of all FACTORS = 2^5 ×11×13 = 4576 required no. = 4576-20 = 4556 mark brainliest and follow ✌️✌️

Find the smallest number which leaves remainders 2, 6 and 12 when divided by 22, 26 and 32 respectively please send me important

Answer»

Here (22-2)=20, (26-6)=20, (32-12) = 20.

.°. REQUIRED no. = (LCM 22,26,32)-20

22 = 2×11

26 = 2×13

32 = 2×2×2×2×2 = 2^5

LCM = highest power of all FACTORS

= 2^5 ×11×13 = 4576

required no. = 4576-20 = 4556