1.

Find the smallest number that must be subtracted from those of the numbers in question 2 which are not perfect cubes, to make them perfect cubes. What are the corresponding cube roots?

Answer»

In previous question there are three numbers which are not perfect cubes. 

(i) 130 

Apply subtraction method, 

130 – 1 = 129 

129 – 7 = 122 

122 – 19 = 103 

103 – 37 = 66 

66 – 61 = 5 

∵ Next number to be subtracted is 91, which is greter than 5 

Hence, 130 is not a perfect cube. So, to make it perfect cube we subtract 5 from it. 

130 – 5 = 125 (which is a perfect cube of 5) 

(ii) 345 

Apply subtraction method, 

345 – 1 = 344 

344 – 7 = 337 

337 – 19 = 318 

318 – 37 = 281 

281 – 61 = 220 

220 – 91 = 129 

129 – 127 = 2 

∵ Next number to be subtracted is 169, which is greter than 2 

Hence, 345 is not a perfect cube. So, to make it a perfect cube we subtract 2 from it. 

345 – 2 = 343 (which is a perfect cube of 7) 

(iii) 792 

Apply subtraction method, 

792 – 1 = 791 

791 – 7 = 784 

784 – 19 = 765 

765 – 37 = 728 

728 – 61 = 667 

667 – 91 = 576 

576 – 127 = 449 

449 – 169 = 280 

280 – 217 = 63 

∵ Next number to be subtracted is 271, which is greter than 63 

Hence, 792 is not a perfect cube. So, to make it a perfect cube we subtract 63 from it. 

792 – 63 = 729 (which is a perfect cube of 9)



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