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Find the smallest number that must be subtracted from those of the numbers in question 2 which are not perfect cubes, to make them perfect cubes. What are the corresponding cube roots? |
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Answer» In previous question there are three numbers which are not perfect cubes. (i) 130 Apply subtraction method, 130 – 1 = 129 129 – 7 = 122 122 – 19 = 103 103 – 37 = 66 66 – 61 = 5 ∵ Next number to be subtracted is 91, which is greter than 5 Hence, 130 is not a perfect cube. So, to make it perfect cube we subtract 5 from it. 130 – 5 = 125 (which is a perfect cube of 5) (ii) 345 Apply subtraction method, 345 – 1 = 344 344 – 7 = 337 337 – 19 = 318 318 – 37 = 281 281 – 61 = 220 220 – 91 = 129 129 – 127 = 2 ∵ Next number to be subtracted is 169, which is greter than 2 Hence, 345 is not a perfect cube. So, to make it a perfect cube we subtract 2 from it. 345 – 2 = 343 (which is a perfect cube of 7) (iii) 792 Apply subtraction method, 792 – 1 = 791 791 – 7 = 784 784 – 19 = 765 765 – 37 = 728 728 – 61 = 667 667 – 91 = 576 576 – 127 = 449 449 – 169 = 280 280 – 217 = 63 ∵ Next number to be subtracted is 271, which is greter than 63 Hence, 792 is not a perfect cube. So, to make it a perfect cube we subtract 63 from it. 792 – 63 = 729 (which is a perfect cube of 9) |
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