1.

Find the smallest number that has to be subtracted from 256, so that it becomes exactlydivisible by 10?9.

Answer»

1 divide 256 by 10

2 the remainder will be=6

ans = 6(it is the smallest no which should be subtracted from 256 so that it is exactly divisible by 10)

When we divide 256 by 10 , the quotient is 25 and the remainder is 6

256= 25×10 + 6

Hence 6 is the smallest no. to be subtracted to 256 so that it is divisible by 10 = 256-6=250



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