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Find the smallest number that has to be subtracted from 256, so that it becomes exactlydivisible by 10?9. |
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Answer» 1 divide 256 by 10 2 the remainder will be=6 ans = 6(it is the smallest no which should be subtracted from 256 so that it is exactly divisible by 10) When we divide 256 by 10 , the quotient is 25 and the remainder is 6 256= 25×10 + 6 Hence 6 is the smallest no. to be subtracted to 256 so that it is divisible by 10 = 256-6=250 |
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