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Find the smallest no which when increased by 7 will completely divisible by 18,21,24 |
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Answer» Answer:497 Step-by-step explanation: SIMPLY TAKE OUT THE LCM OF THESE 3 AS FOLLOWS: THE FACTORS FORMED ARE (3,3,2,2,2,7);MULTIPLY THEM AND SUBTRACT 7 FROM THIS: IT FORMS (504) SUBTRACT 7 =(497) ANSWER VOTE FOR ME HOPE IT HELPS YOU :) :) |
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