1.

Find the smallest no which when increased by 7 will completely divisible by 18,21,24

Answer»

Answer:497

Step-by-step explanation:

SIMPLY TAKE OUT THE LCM OF THESE 3 AS FOLLOWS:

THE FACTORS FORMED ARE (3,3,2,2,2,7);MULTIPLY THEM AND SUBTRACT 7 FROM THIS: IT FORMS (504)

SUBTRACT 7

=(497) ANSWER

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