Find the smallest 5- digit number which is exactly divisible by 15, 24

1.	Find the smallest 5- digit number which is exactly divisible by 15, 24 and 40.
Answer» ong>Answer: $\huge\boxed{\fcolorbox{red}{Orange}{Answer}}$ Factors of 15 = 3x5 24 = 2x2x2x3 40 = 2x2x2x5 LCM = 2x2x2x3x5 = 120 10000/120 = 83.3 84*120 = 10080. So 10080 is the smallest 5-digit NUMBER divisible by 15, 24 and 40. ☺☺☺Hope it HELPS you ✌✌✌

Find the smallest 5- digit number which is exactly divisible by 15, 24 and 40.

Answer»

ong>Answer:

$\huge\boxed{\fcolorbox{red}{Orange}{Answer}}$

Factors of

15 = 3x5

24 = 2x2x2x3

40 = 2x2x2x5

LCM = 2x2x2x3x5 = 120

10000/120 = 83.3

84*120 = 10080.

So 10080 is the smallest 5-digit NUMBER divisible by 15, 24 and 40.

☺☺☺Hope it HELPS you ✌✌✌

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Find the smallest 5- digit number which is exactly divisible by 15, 24 and 40.​

Factors of

15 = 3x5

24 = 2x2x2x3

40 = 2x2x2x5

LCM = 2x2x2x3x5 = 120

10000/120 = 83.3

84*120 = 10080.

So 10080 is the smallest 5-digit NUMBER divisible by 15, 24 and 40.

☺☺☺Hope it HELPS you ✌✌✌

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Find the smallest 5- digit number which is exactly divisible by 15, 24 and 40.