1.

Find the roots of the quadratic equation 3x2 -2/6x +2-0.

Answer»

3x2- 2√6x+ 2 = 0

⇒ 3x2- √6x -√6x+ 2 = 0

⇒ √3x[√3x- √2] - √2 [√3x- √2] = 0

⇒ [√3x- √2] [√3x- √2] = 0

⇒ [√3x- √2] = 0 or [√3x- √2] = 0

⇒x= √2 / √3 orx= √2 / √3

so.x= √2 / √3 , √2 / √3 is the solution


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